64-bit operating system vs 32-bit code

[krispiekream]

Hi,

I am code an old code from 32-bit system and tried to run on 64-bit system. Do you think it is easier for me to change my computer (cloud) to 32-bit or to change the code to make it work with 64-bit system?

i am not sure if the drivers are available in 64-bit but it will take me some time to figure that out by running each vi individually. Any advice is appreciated.

Thanks

Krispiekream

[Gregory]

I've always used 32-bit LabVIEW on 64-bit Windows. As long as your application uses <2 GB of RAM I don't think you'll notice a difference. 

[crossrulz]

Windows still has the WOW layer (Windows On Windows) to handle 32-bit applications in a 64-bit OS.  So I would not worry about this too much.

[altenbach]

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@krispiekream wrote:

I am code an old code from 32-bit system and tried to run on 64-bit system.

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You left out the most important information: What happens when you try to run it???

If it works, you are all set! 😄

(... and if it does not work, the problem might not be in the OS bitness, but elsewhere. You should be able to
:make it work" as 32bit application on a 64bit OS with a few tweaks. That's definitely the easiest approach.)

[krispiekream]

so i cant copy 64-bit vi onto 32-bit vi right?  it allows me to copy and paste by doesnt allow me to write it on double click on it to select the fuctions. 

i have input data but 0 data output. i was told that my LLB is corrupted but i am not sure. 

[krispiekream]

test files

[altenbach]

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@krispiekream wrote:

so i cant copy 64-bit vi onto 32-bit vi right?  it allows me to copy and paste by doesnt allow me to write it on double click on it to select the fuctions. 

i have input data but 0 data output. i was told that my LLB is corrupted but i am not sure. 

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Plain VIs (without external non-LabVIEW code such as DLLs) will run unchanged on any bitness. If you have external code such as DLLs, that needs to match the LabVIEW bitness. What is the corrupt llb you are talking about?

[altenbach]

Also have a look here.