Calculate area of an anomalous object

[adobefree@gmail.com]

i wanna to calculate the area of an anomalous object , not the bounding box , any idea?

[muks]

In particle analysis you have "Perimeter" you can use this.

[muks]

Post an image if you can

[shrekt]

hi,

Wondering if the following link help you to solve your problem.

http://en.wikipedia.org/wiki/Polygon

Regards

[adobefree@gmail.com]

post the image as above

[ben64]

Since the picture is black and white, "white pixels/total pixels X picture area" would give you the area of the white objects. You could try the Read BMP.vi (or read jpeg, png) and the Unflatten Pixmap VI to get the 1-bit pixmap which is a 2d array of boolean. Maybe this could work.

Ben

[Hummer1]

Image to array and then count the number of nonzero array elements...that might work.

Hummer1

(if you have a conversion between pixel size and physical size you could then do the math...)

[adobefree@gmail.com]

i used to believe that the above method can only get the total area ,not the area of each object , am i right? 

or first use particle analysis to get the bounding box , then count the nonzero pixels in the bounding ROI?

Message Edited by adobefree@gmail.com on 12-02-2009 08:26 PM

[GerdW]

Hi adobe... (is this your real email address???),

which post are you referring to ("the above method")?

Anyway: what's wrong with counting the pixels of each color? Easiest and probably surely faster than to calc the area based on area border...

[adobefree@gmail.com]

Hi adobe... (is this your real email address???),

    Yes exactlly

which post are you referring to ("the above method")?

    i was refer to the method that converting a image to a U8 array , then count the nozero pixels number

Anyway: what's wrong with counting the pixels of each color? Easiest and probably surely faster than to calc the area based on area border...

    it's ok , but i was wondering is there any direct measurement, since ni can get the bounding box, why not give the real

area directly?