@crossrulz wrote:
I could have sworn I saw people put multiple variables into a PrintLn command. But after some quick Googling, I can see I was wrong. So you will need something like this then:
Serial.Print(voltagesensor);
Serial.Print(",");
Serial.PrintLn(current);
I'm sure you can. Serial.Print or serial.println is sending a string. So when you separate things by commas, you are sending 3 parameters when the function only looks for one string. If you Concatenate the 3 values together, it should make a single parameter of a string.
Serial.PrintLn(voltagesensor & "," & current);
