Wrong result in match pattern

[labmaster]

Hi, I want to extract the space (sometimes, !#" etc) from "@020 12345' using match pattern function.

When I used [\s!#"] as a regular expression, the result "20".

Why my expression is not worked and Can you propose more suitable expression?

labmaster 

*)Enclosed is the VI example in LV2009

[altenbach · Accepted solution]

Your string indicator is set to hex display. 0x20 is a space, right? 😉

[altenbach]

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@labmaster wrote:

Hi, I want to extract the space (sometimes, !#" etc) from "@020 12345' using match pattern function.

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You should also describe what you mean by "extract". If you simply need a space, you can use a space diagram constant. No need to extract it. Do you want the resulting string without the space, for example?

I am sure one of the regex gurus here will jump right on this one... 😉

[labmaster]

Wow, I had a mistake to interprete the indicator. Happen to be "20".

Thanks.

labmaster.