Remove a Carriage Return from a string in CVI

[jschafer10272]

I have the following string in CVI/Labwindows:

Sat Apr 20, 2005 20:00:00 CR


Is there a way to manipulate the string to remove the CR????

[RobertoBozzolo]

Sure.
Supposing you want to keep the first characters of the string, simply set string[n-1] = 0: this terminates the string discarding all that follows.

[Erwin Timmerman]

I have made a simple routine which deletes all space characters (spaces, new lines, CR etc) from the end of a line.
Can come in handy for this problem, but also for some future need.

Good luck!

int StringDeleteSpaceAtEnd(char *String)
{ int StrLen, i;
// deletes spaces, newlines, tabs etc at the end of a string
// returns the remaining stringlength
if (!String) return 0;
StrLen = strlen(String); if (!StrLen) return 0;
for (i=StrLen-1; i>=0; i--) {
if (isspace(String[i])) String[i] = 0;
else return (i+1);
}
return 0;
}

[jjvema]

You can use:

strncpy(STR_TARGET,STR_SOURCE,strlen(STR_SOURCE)-2);

The function strncpy delete the latest 2 bytes of STR_SOURCE

[RobertoBozzolo]

---

jjvema ha scritto:

You can use:

strncpy(STR_TARGET,STR_SOURCE,strlen(STR_SOURCE)-2);

The function strncpy delete the latest 2 bytes of STR_SOURCE

---

Take care when using strncpy as this command does not terminate the copied string: you should add STR_TARGET[strlen(STR_SOURCE)-2] = 0; or better use the toolbox function StrinCopyMax which has a series of advantages highlighted in the online help.