Multifunction DAQ

cancel
Showing results for 
Search instead for 
Did you mean: 

Measuring Current with NI6250

Solved!
Go to solution

Hi,

 

I'm using the NI 6250 for some Analog input analysis.  In addition I want to measure the current I supply to Unit under test.  The current is approximately 300ma.

I thought to use a 2 ohm shunt resistor, thus to lower the supply voltage by 0.6V and not having too low voltage for measurements.  I plan to adjust the supply votage to 9.6 V so that after the shunt resistor, I'll get 9V as I'm suppose to provide.

 

1. Any remarks or better suggestions for that?

 

2.  I will calculate the current by measuring the voltage over the resistor.  The question is shall i use 2 single inputs or a differential input?

 

3.  Looking in Table 4-3, page 4-12 of the DAQ M Series - User Manual, I see a recommended application of a differential input voltage.  There, they put 2 pull down resistor to ground.  Is this what I need to do as well?  Can't I just apply the 2 lines from the resistor, directly to the diff. input?

 

4. Am I suppose to connect the AGND to my supply GND?

 

Thanks

Rafi

0 Kudos
Message 1 of 4
(3,099 Views)

Well, depending on your load and your source I would try a current measurement with a 0.2 Ohm shunt (4 wire) in the ground line with differential measurement in the +/- 100mV range.( gives you a 500mA current range)

With 9V you might use the shunt in the high side and use a differential channel.Take a look at the specs.

If your source has sensing capabilities you might even compensate the voltage drop on the shunt.

 

Greetings from Germany
Henrik

LV since v3.1

“ground” is a convenient fantasy

'˙˙˙˙uıɐƃɐ lɐıp puɐ °06 ǝuoɥd ɹnoʎ uɹnʇ ǝsɐǝld 'ʎɹɐuıƃɐɯı sı pǝlɐıp ǝʌɐɥ noʎ ɹǝqɯnu ǝɥʇ'


0 Kudos
Message 2 of 4
(3,082 Views)

Hi Henrik

 

Thank you for your response.

 

Actually, I had difficulties to obtain a 9V power supply (15W).  Therefore, I decided to take a 12V ps, trimmed down (by the supplier) to 9.6V.  Now, all I need is to use a 2 ohm resistor with 300mA current and I get a nice 9V for the Unit under test.  My PS does not have sense lines.

 

Another consideration in selecting the shunt resistor was not to use a too low voltages.  With 2 ohms I get 0.6 Volts.  My UUT can tolerate the little voltage drop since, eventually, it regulate it down to 3.3V.

 

I was looking for advice whether to use a differential measurement or 2 single ended measurements...and whether I need pull down resistor if I use a differential measurement.

 

Thanks

RK

0 Kudos
Message 3 of 4
(3,077 Views)
Solution
Accepted by topic author Rafi2003

In your case the diffential measurement is the way to go. You don't need any more bias current (pulldown) resistors if your PS is connected to (A)GND somewhere anyway.

Greetings from Germany
Henrik

LV since v3.1

“ground” is a convenient fantasy

'˙˙˙˙uıɐƃɐ lɐıp puɐ °06 ǝuoɥd ɹnoʎ uɹnʇ ǝsɐǝld 'ʎɹɐuıƃɐɯı sı pǝlɐıp ǝʌɐɥ noʎ ɹǝqɯnu ǝɥʇ'


Message 4 of 4
(3,046 Views)