03-09-2010 03:16 PM
Hi dears,
An important question came to my mind while doing some test that I am sure it is very trivial to all of u, but scaring from any damages to DAQs , I 'll ask my question here:
one of the specification of analog output of DAQs is current limitation for me is 5mA.
I wanna to use the the analog output as a DC voltage supply, now I am wondering if this current is the same as the current passes through the circuit that is fed by Ao.
To be clear, assume O connect the Ao across a resistor, then the current in circuit will be : V(AO)/R =I, if this I is the same as the I in the DAQ data sheet?
Thanks dudes,
03-10-2010 05:55 AM
YES, Ohms law is still valid, however are you shure that your load is a real R? Maybe your load impedance is also a little bit complex and your output is ???kHz instead of DC?
If you need more current and/or want to protect your output you can simply build up a voltage follower with an OP-Amp of your choice .
03-11-2010 10:55 AM
HI Henri,
Thanks for your response.
Actually, my circuit is including different components such as MOSFETs and.... If I used the resistor just to clarify my meaning.Otherwise surely, the ohm law is valid.Let me describe why that question came to my mind:
I was testing my circuit in the lab before connecting to the DAQ and I was using a benchtop DC voltage supply. Suddenly I noticed the current on the Voltage source display is not the same as the current passes through the circuit, it was very small ( we called it pulling current) so this question came to my mind that may the current restriction in the datasheet of AO ports of a DAQ is this current(pulling current) not the current Thru the circuit!