how to make active status expression in step setting -> properties-> expression?

[Amitabh_Bachhan]

Hi,

hello to eveone as this is my first question in forum and new to TestStand 2013. I am trying to modify existing teststand program and want to reduce number of iteration from 3 to 1 . But currently status expression box in step setting-> properties - expression is grayed out and looks I can't modified previously written expression there. what should I do? Current expression is

(Step.Result.Status == "Done" && (Step.TS.SData.ThreadOpt == 0 || Step.TS.SData.ThreadOpt == 3)) ? "Passed" : Step.Result.Status and I want to change 3 to 1(only one iteration).

Regards,

Amitabh Bhachhan 

[~jiggawax~]

What kind of a step is this?

The default status expression is defined in the step definition in the type palette.  If this is a native step then you don't want to change it.  You want to create your own step type and re-define the status.

If a step type is written well, you should be able to change those values through the edit substep. 

If you are absolutely, postively sure you want to change it without creating a new step type then you can use the API to do so.

Can you give us more detail?  We will be able to better help you.

Thanks,

[dug9000]

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@Amitabh_Bachhan wrote:

Hi,

hello to eveone as this is my first question in forum and new to TestStand 2013. I am trying to modify existing teststand program and want to reduce number of iteration from 3 to 1 . But currently status expression box in step setting-> properties - expression is grayed out and looks I can't modified previously written expression there. what should I do? Current expression is

(Step.Result.Status == "Done" && (Step.TS.SData.ThreadOpt == 0 || Step.TS.SData.ThreadOpt == 3)) ? "Passed" : Step.Result.Status and I want to change 3 to 1(only one iteration).

Regards,

Amitabh Bhachhan 

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How does editing the status expression help you change the number of iterations? I think you are misunderstanding the purpose and implementation of this expression. The 3 in the above expression has nothing to do with number of iterations.

-Doug