Averaging Vectors

[ssmith490D]

What I need is specific VI names not general info, if there are any. Or do I have to, using math trig VIs, do the vector math one step at a time??

ssmith

[altenbach]

Are your vectors in 2D or 3D? What is your LabVIEW version?

Message Edited by altenbach on 08-17-2009 11:03 AM

[Ben]

Here is a Snippet.

 

 I take two 1-d arrays of doubles that have the U and V vector components. I convert to complex find the total and divide by the number of components. then I divide to find the average and then convert the complex back to polar to get the Uavg and Vavg values.

I think this will do 3d but I have not thought about to hard or tested either.

Ben

Message Edited by Ben on 08-17-2009 01:12 PM

[ssmith490D]

I have version 8.6. The vector is wind speed and wind direction. It has not yet been resolve into it's u and v components. This is the first part of the problem. Then averaging the u and v components is the middle. The last part, and again difficult part is merging the u and v  components back into a speed and direction vector.

ssmith

[Ben]

But Ben!

Those look rubes. Why not just average each vector seperately?

Good point. Lets just call those two VIs a test to see if Ican create a snippet.

Ben

[Ben]

Wind speed is "r" and the direction is theta.

The example above is the answer to your question turned inside out.

Ben

[ssmith490D]

Correct! Once the single vector is resolved into it's components each component is averaged. Then you take the average of the u and v and then then construct back to a single vector.

ssmith

[Ben]

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ssmith490D wrote:

Correct! Once the single vector is resolved into it's components each component is averaged. Then you take the average of the u and v and then then construct back to a single vector.

ssmith

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Aggreed.

Ben

[Darin.K]

If you are starting with magnitude and direction, why not use Polar to Complex, use Ben's code to average, then Complex to Polar to return average magnitude and direction.

[ssmith490D]

Because until now I didn't have the info you just gave me! (The name of the vi) LOL! Thanks alot. I'll try it and let you know.

ssmith