07-30-2018 02:45 PM
Hello I am trying to set up a PDelta Meas between the Keithley 6221 and 2182A, however I can't get the Delta meas example to work.
I keep getting error 85 (Scan From String (arg 1) in Keithley 622x.lvlib:KE622x -- 2182 -A Check For SCPI Errors.vi->Keithley 622x.lvlib:KE622x -- 2182 -A Set Auto Range State.vi->Keithley 622x.lvlib:KE622x -- 2182 -A Set Params.vi->Keithley 622x.lvlib:KE622x -- Execute Delta Meas.vi->Delta Meas Example 6221.vi)
Can anyone help.
Solved! Go to Solution.
07-30-2018 02:47 PM
I forgot to include the example.
07-31-2018 06:33 PM
Hi,
Have you read this document about the error that you are having?
08-01-2018 09:30 AM
I did read that, and allow the solutions fail.
I found the issue was my files were set to read only.
09-19-2018 01:29 AM
Hello together,
I have the same problem with the example programm. I get the same error message, but i don´t understand the solution. I´m new to LabView, can somebody tell me which change I have to do?
Many thanks in advance.
09-19-2018 10:16 AM
When you download the driver from Keithley, it's set to read only meaning you can't make changes to any the instruments drivers. Deselect read all in the driver properties. once you deselect read all use debug mode to find where problems show up. Go down this rabbit hole until you reach scan to string. fix scan to string by converting it to a number.
09-20-2018 01:44 AM
Thanks for the feedback. I took away the copy protection. Afterwards I went down step by step into the Programm.
I get this failure code.
Fehler 85 bei In String suchen (arg 1) in Keithley 622x.lvlib:Error Query.vi->Keithley 622x.lvlib:KE622x -- 2182 -A Write.vi->Keithley 622x.lvlib:KE622x -- 2182 -A Set Digital Filter Count.vi->Keithley 622x.lvlib:KE622x -- 2182 -A Set Params.vi->Keithley 622x.lvlib:KE622x -- Execute Delta Meas.vi->Keithley 622x.lvlib:KE622x -- Delta Meas Example.vi
So I went into Error Query, but I can not find the mistake in this VI. There are 2 scan in string. Can you exactly tell me where I have to change something? I tried it almost a hundred times with the highlight function, but I don´t get it.
Thanks a lot.
09-21-2018 11:00 AM - edited 09-21-2018 11:05 AM
Hello Steve,
Did you follow the additional steps in the link provided above?
09-24-2018 08:27 AM
Hi, yes I followed it, but I couldn´t find something helpful.
But I´ve checked again the code with the highlight function. The problem is not the formattting of the scan. The failure occurs, because after a few repeats of the error query VI, the readed string from the buffer is empty.
Normally the string contains "0, no error", but when the failure appears, the string is " ".
So the scan isn´t the problem, I think the commands are the problem. But I don´t have an idea what the problem is.
10-27-2024 02:37 AM
I'm getting the same problem. Have you found a solution to this problem? It will be very helpful for me if you can tell me the solution.