11-14-2012 06:46 AM
Hi all
I have some problem with the lap time, i need to stop the timer when the indicator reach the 0 , at the moment i can do it but the array catch all the time during the indicator is on 0 ..... how can i take only one time per lap?
Thanks
11-14-2012 09:46 AM
take a look at the code here to get a hint...
11-15-2012 01:39 AM
I'm not able to apply it to my VI can you help me?
11-15-2012 07:27 AM
11-21-2012 03:05 AM
Could you send me the modyfied VI?
Thanks
11-21-2012 05:06 PM
Apok- Multi-element shift registers are not something I've encountered yet, and the help is a little light in explaining them. If I understand correctly, during the ith iteration of the loop, the top element of the LH shift register carries what was placed on the RH shift register at the completion of the (i-1)th iteration, the next one down what was placed on the RH SR at the completion of the (i-2)th iteration, etc. Is this the way it works? interesting.....
Jeff
11-21-2012 05:22 PM - edited 11-21-2012 05:22 PM
Why so complicated? SImply use another "elapsed time" express VI.
Use a numeric indicator with a time format and you can eliminate all your formatting.
(I did not look at the rest of your code, but it seems pretty incomprehensible :D)
11-22-2012 02:42 AM
Altenbach thank you for semplifying the Vi but i didn't reach my target!!
I need the lap time! I need to see the lap time every time the gauge reach 10!
At the moment i can see the lap time in the array but the array take many lap times because it wait that the transaction change.... I need only one time lap per lap.
Ex
- 97.6963 (after 1 complete lap)
- 195.2 (after 2 complete lap)
ecc
You are right the Vi is incompprehensible it's not my business hihi
11-25-2012 03:45 AM
help help help!
11-26-2012 11:42 AM
@Teo_CF wrote:
help help help!
Hi, Teo- I have two suggestions/comments for you:
Jeff