format into string 16 bit signed integer

[mitulatbati]

Is there any format specifier string for "Format into string", whereas the result is an I16 string?

My problem is when I use "%d" and the input string is 65535, the result string should be "-1".

[JÞB]

Just convert to I16 first then scan to string

[crossrulz]

Are you trying to get an integer out of an ASCII string (Scan from String) or turn an integer into a string (Format into String).  You title and question seem to contradict each other.

Assuming you are trying to scan from string, it looks like you need to scan into a U16 and then use a conversion bullet to turn it into an I16.

[mitulatbati]

The input of the function is a DBL...

[crossrulz]

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@mitulatbati wrote:

The input of the function is a DBL...

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Then use Jeff's code as an example of what to do.  You just have a double input instead of a U32, U16, etc.

[mitulatbati]

I did it... the result string is 32767 😞

 

[JÞB · Accepted solution]

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@crossrulz wrote:

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@mitulatbati wrote:

The input of the function is a DBL...

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Then use Jeff's code as an example of what to do.  You just have a double input instead of a U32, U16, etc.

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Actually you need two conversions
to do that from dbl  (LabVIEW Minutea that might bite you some day:  Float to int retains sign)

[GerdW]

Hi mitu,

then combine your approach with others shown before:

[mitulatbati]

Hi,

there are some other solutions, in each case the result=-1: