how to solve y=a*x+b,y=c*x+d (a,b,c,d are known constant)in labview?

[charles0601]

how to solve y=a*x+b,y=c*x+d (a,b,c,d are known constant)in labview? any help is appreciated.

[RavensFan]

What are you looking for, the intersection of 2 lines?  Trying to find an x,y pair that satisfies both equations?

That is basic algebra. 

ax+b=cx+d

(a-c)x=d-b

x=(d-b)/(a-c)

Now you have an x, put it back into either original equation to get y.

Message Edited by Ravens Fan on 04-07-2010 11:03 PM

[smercurio_fc]

homework?

[srikrishnaNF]

Hi,

 To solve the linear equations,you can refer the mathematics/linear equations pallette and use  solve linear equations.vi.

Thanks and regards,

srikrishnaNF

[ade77]

Charles ,

This is an example:

[tbob]

Does anyone think Labview could solve this problem:

let a = b

then  a^2 = ab  (multiply both sides by a)

then  a^2 - b^2 = ab - b^2  (subtract b squared from both sides)

then  (a+b)(a-b) = b(a-b)     (factoring)

then  a+b = b                       (divide both sides by a-b)

so if a=1, then b=1

and we get 1+1=1

or 2=1

????????????????????

[johnsold]

NaN

Lynn 

[Mathan]

---

tbob wrote:

Does anyone think Labview could solve this problem:

let a = b

then  a^2 = ab  (multiply both sides by a)

then  a^2 - b^2 = ab - b^2  (subtract b squared from both sides)

then  (a+b)(a-b) = b(a-b)     (factoring)

then  a+b = b                       (divide both sides by a-b)

so if a=1, then b=1

and we get 1+1=1

or 2=1

????????????????????

---

The problem is here

 (a+b)(a-b) = b(a-b)     (factoring)

Since a=b, dividing both sides by (a-b) will give NaN as mentioned by Lynn.

Mathan

[tbob]

Give both of those men a cigar.  That's t he answer.  You would be surprised at how many people, even math wizzes, can't find the answer.