07-28-2009 11:15 AM - edited 07-28-2009 11:15 AM
Hi, I need to know your idea in my numeric series.
For example, consider a series, "1:0.0000011 2:0.0000011 3:0.0000148 4:0.0000022 5:0.0000159 6:0.0000002 7:0.0000148 8:0.0000022 9:0.0000159 10:0.0000002....."
The regular group is just started in index #3 with size of 4 and contained two irregular parts.
My problem is the series can be varied according to my parameters.
Sometime, no irregular part or size of 2....
My question is how to detect "generally" the regular group in a 1D matrix?
Is there some useful technique for this work?
labmaster.
07-28-2009 11:47 AM
Define:
07-28-2009 12:04 PM - edited 07-28-2009 12:07 PM
Sorry for my expression.
I meant the series was created from my private parameters.
Therefore, you don't have to take care about it.
Just think about 1D series contain regular group and irregular part.
The irregular part is started from index #1 all the times.
I have to know you the size of group could be varied in some situations.
labmaster.
07-28-2009 12:11 PM
I read then re-read then
Please slow down and gothrough a couple of your examples and show us which part is which.
Ben
07-28-2009 12:16 PM
The length is irrelevant. Use the match regular expression function.
Is this what you wanted to do?
07-28-2009 12:20 PM
It also works the same way if the 1st part of the expression is what is varied.
07-28-2009 12:51 PM - edited 07-28-2009 12:53 PM
Let's consider one more example: "numeric series"
1, 2, 3, 4, 5, 3, 4, 5, 3, 4, 5, 3, 4, 5,...., 3, 4, 5, ....
(My real series is expressed in double precision number)
Each number have a proper index in this series.
The irregular part: "1, 2"
The minimum regular group part: "3, 4, 5"
The starting index of regular part: 3 (when the first is 1)
Do you understand my question?
It is related to grouping.
labmaster.
07-28-2009 01:00 PM
07-28-2009 02:06 PM
I did.
A big index was selected. then find it again -> size of group.
labmaster.
07-28-2009 02:08 PM
Dennis, nice to meet you.
just for explanation with start index = 1.
labmaster.