02-26-2015 03:14 AM
hello;
For the NI 6008 card sampling frequency equal to 10 kS / s and it has 8 analog inputs, but if I will use the 8 analog inputs simultaneously, what is the value of the new échantionnage frequency for each input analog obtained during an acquisition in labview?
02-26-2015 06:23 AM
From what I can gather from the data sheet, each channel will be sampled at the 10kS/s.
02-26-2015 06:53 AM
Thank you for the answer, but according to the datasheet, the 8 analog inputs have a single ADC and a multiplexer connected before to the ADC allows the passage of all analog signals, so I don't know if 10 KS / s is achieved in all inputs when used simultaneously !!
02-26-2015 07:29 AM
The data sheet also says the maximum sample rate for multiple channels is 10kS/s aggegate. I take this to mean that the entire channel sweep is done at 10kHz.
You could always try it and see what happens. Read all 8 channels as a waveform with the sample rate set to 10KHz and see what the dt is in the waveform.
02-26-2015 08:32 AM
02-26-2015 09:10 AM - edited 02-26-2015 09:16 AM
Thank you for your answer, but the 10 KS / s given in the datasheet of the card NI 6008, is it the maximum sample rate per channel or the aggregate rate ?
02-26-2015 11:48 AM