LabVIEW
How to search and delete multiple matches from 1D array?
ttrr, I don't think Astorboy has 7.1. BTW, why does your example have my name? 
Astroboy, your algorithm is still wrong. The only reason it worked is because you have N,xxx,N,xxx. If you had two xxx's in a row it wouldn't work. Here's another option, but this is also not very good for large arrays, although ttrr's is probably better (at least for strings). You can bench them and try.
For a more complex algorithm, you can try determining the number (and indexes) of elements to remove, initializing a new array and using Array Subset on the original and Replace Array Subset on the new one. You will obviously need to calculate the length and indexes.
As explaned in this recent post, it is extremely inefficient to use "delete from array" inside a loop for this purpose. You should use "replace array element" and trim the unused tail at the end. This is much more efficient!
The attached example (LabVIEW 7.0) shows a quick modification of your VI to implement this (Basically the "replace II" algoritm mentioned in the above link) . In case of large arrays, it will be much more efficient. Let me know if you have any questions. 🙂
Message Edited by altenbach on 08-14-2005 06:35 PM
Devanshi@2020 wrote:
Here !
Other than the fact that you're replying to a 19 year old thread, your solution is both inefficient (I'm guessing altenbach's comments above have some details) and not fully correct. For example, see what happens if add another 3 to your original array.
